Base | Representation |
---|---|
bin | 101100010001100101101… |
… | …010010101000001000001 |
3 | 101202212100000101011200001 |
4 | 230101211222111001001 |
5 | 344322111331044023 |
6 | 10245420311400001 |
7 | 432550016014642 |
oct | 54214552250101 |
9 | 11685300334601 |
10 | 3042542440513 |
11 | a73375985a24 |
12 | 4117b9383001 |
13 | 190bab551224 |
14 | a738d0016c9 |
15 | 5422453b6ad |
hex | 2c465a95041 |
3042542440513 has 2 divisors, whose sum is σ = 3042542440514. Its totient is φ = 3042542440512.
The previous prime is 3042542440481. The next prime is 3042542440543. The reversal of 3042542440513 is 3150442452403.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3014032793409 + 28509647104 = 1736097^2 + 168848^2 .
It is a cyclic number.
It is not a de Polignac number, because 3042542440513 - 25 = 3042542440481 is a prime.
It is not a weakly prime, because it can be changed into another prime (3042542440543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1521271220256 + 1521271220257.
It is an arithmetic number, because the mean of its divisors is an integer number (1521271220257).
Almost surely, 23042542440513 is an apocalyptic number.
It is an amenable number.
3042542440513 is a deficient number, since it is larger than the sum of its proper divisors (1).
3042542440513 is an equidigital number, since it uses as much as digits as its factorization.
3042542440513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 3042542440513 its reverse (3150442452403), we get a palindrome (6192984892916).
The spelling of 3042542440513 in words is "three trillion, forty-two billion, five hundred forty-two million, four hundred forty thousand, five hundred thirteen".
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