Base | Representation |
---|---|
bin | 1101110101111101010111… |
… | …00011000010001000110011 |
3 | 10222210011100022210100021111 |
4 | 12322332223203002020303 |
5 | 12442222301144030413 |
6 | 144424313444134151 |
7 | 6261212033564266 |
oct | 672765343021063 |
9 | 128704308710244 |
10 | 30441311314483 |
11 | 97770a66a7473 |
12 | 34b7891697357 |
13 | 13ca7ac6c9a74 |
14 | 77351dd44cdd |
15 | 37bcad381d3d |
hex | 1bafab8c2233 |
30441311314483 has 2 divisors, whose sum is σ = 30441311314484. Its totient is φ = 30441311314482.
The previous prime is 30441311314457. The next prime is 30441311314499. The reversal of 30441311314483 is 38441311314403.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30441311314483 - 29 = 30441311313971 is a prime.
It is not a weakly prime, because it can be changed into another prime (30441311014483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15220655657241 + 15220655657242.
It is an arithmetic number, because the mean of its divisors is an integer number (15220655657242).
Almost surely, 230441311314483 is an apocalyptic number.
30441311314483 is a deficient number, since it is larger than the sum of its proper divisors (1).
30441311314483 is an equidigital number, since it uses as much as digits as its factorization.
30441311314483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 40.
Adding to 30441311314483 its reverse (38441311314403), we get a palindrome (68882622628886).
The spelling of 30441311314483 in words is "thirty trillion, four hundred forty-one billion, three hundred eleven million, three hundred fourteen thousand, four hundred eighty-three".
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