30444140113 has 2 divisors, whose sum is σ = 30444140114. Its totient is φ = 30444140112.

The previous prime is 30444140081. The next prime is 30444140131. The reversal of 30444140113 is 31104144403.

Together with next prime (30444140131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22842392769 + 7601747344 = 151137^2 + 87188^2 .

It is a cyclic number.

It is not a de Polignac number, because 30444140113 - 2⁵ = 30444140081 is a prime.

It is not a weakly prime, because it can be changed into another prime (30444140143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15222070056 + 15222070057.

It is an arithmetic number, because the mean of its divisors is an integer number (15222070057).

Almost surely, 2^30444140113 is an apocalyptic number.

It is an amenable number.

30444140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

30444140113 is an equidigital number, since it uses as much as digits as its factorization.

30444140113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 30444140113 its reverse (31104144403), we get a palindrome (61548284516).

The spelling of 30444140113 in words is "thirty billion, four hundred forty-four million, one hundred forty thousand, one hundred thirteen".