Base | Representation |
---|---|
bin | 11100010111000101… |
… | …010000100000111011 |
3 | 2220121020212011122201 |
4 | 130113011100200323 |
5 | 444331204303103 |
6 | 21553420331031 |
7 | 2125425642112 |
oct | 342705204073 |
9 | 86536764581 |
10 | 30452025403 |
11 | 11a07413448 |
12 | 5a9a3a3a77 |
13 | 2b43c20957 |
14 | 168c4b2c79 |
15 | bd366751d |
hex | 71715083b |
30452025403 has 4 divisors (see below), whose sum is σ = 30453937488. Its totient is φ = 30450113320.
The previous prime is 30452025377. The next prime is 30452025419.
30452025403 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30452025403 - 229 = 29915154491 is a prime.
It is a super-2 number, since 2×304520254032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30452025103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 931951 + ... + 964072.
It is an arithmetic number, because the mean of its divisors is an integer number (7613484372).
Almost surely, 230452025403 is an apocalyptic number.
30452025403 is a deficient number, since it is larger than the sum of its proper divisors (1912085).
30452025403 is a wasteful number, since it uses less digits than its factorization.
30452025403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1912084.
The product of its (nonzero) digits is 14400, while the sum is 28.
It can be divided in two parts, 304520 and 25403, that added together give a palindrome (329923).
The spelling of 30452025403 in words is "thirty billion, four hundred fifty-two million, twenty-five thousand, four hundred three".
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