Base | Representation |
---|---|
bin | 101100010100011001100… |
… | …001111001101000000011 |
3 | 101210011010022200200111020 |
4 | 230110121201321220003 |
5 | 344344301343130201 |
6 | 10251035551120523 |
7 | 433014550654425 |
oct | 54243141715003 |
9 | 11704108620436 |
10 | 3045560130051 |
11 | a7468432881a |
12 | 4122bbb13143 |
13 | 19126c7ba33a |
14 | a7597ad0815 |
15 | 5434e426a36 |
hex | 2c519879a03 |
3045560130051 has 8 divisors (see below), whose sum is σ = 4063553167104. Its totient is φ = 2028970256520.
The previous prime is 3045560130017. The next prime is 3045560130073. The reversal of 3045560130051 is 1500310655403.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3045560130051 - 213 = 3045560121859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3045560129994 and 3045560130021.
It is not an unprimeable number, because it can be changed into a prime (3045560130001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 350785815 + ... + 350794496.
It is an arithmetic number, because the mean of its divisors is an integer number (507944145888).
Almost surely, 23045560130051 is an apocalyptic number.
3045560130051 is a deficient number, since it is larger than the sum of its proper divisors (1017993037053).
3045560130051 is a wasteful number, since it uses less digits than its factorization.
3045560130051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 701581761.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 3045560130051 its reverse (1500310655403), we get a palindrome (4545870785454).
The spelling of 3045560130051 in words is "three trillion, forty-five billion, five hundred sixty million, one hundred thirty thousand, fifty-one".
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