3050221214113 has 4 divisors (see below), whose sum is σ = 3050225478448. Its totient is φ = 3050216949780.

The previous prime is 3050221214101. The next prime is 3050221214137. The reversal of 3050221214113 is 3114121220503.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3050221214113 - 2⁵ = 3050221214081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3050221214153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 768531 + ... + 2586712.

It is an arithmetic number, because the mean of its divisors is an integer number (762556369612).

Almost surely, 2^{3050221214113} is an apocalyptic number.

It is an amenable number.

3050221214113 is a deficient number, since it is larger than the sum of its proper divisors (4264335).

3050221214113 is an equidigital number, since it uses as much as digits as its factorization.

3050221214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4264334.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 3050221214113 its reverse (3114121220503), we get a palindrome (6164342434616).

The spelling of 3050221214113 in words is "three trillion, fifty billion, two hundred twenty-one million, two hundred fourteen thousand, one hundred thirteen".