Base | Representation |
---|---|
bin | 1101110111101111001110… |
… | …10010010110001001111011 |
3 | 11000000000010201001120122020 |
4 | 12323313213102112021323 |
5 | 12444223000414141011 |
6 | 144512343502525523 |
7 | 6265504655403321 |
oct | 673674722261173 |
9 | 130000121046566 |
10 | 30502443115131 |
11 | 97a0016a3a069 |
12 | 35076b25968a3 |
13 | 14034a2790380 |
14 | 77647cc53d11 |
15 | 37d68a14d006 |
hex | 1bbde749627b |
30502443115131 has 32 divisors (see below), whose sum is σ = 45615670990848. Its totient is φ = 18006185796480.
The previous prime is 30502443115103. The next prime is 30502443115147. The reversal of 30502443115131 is 13151134420503.
It is not a de Polignac number, because 30502443115131 - 25 = 30502443115099 is a prime.
It is a super-2 number, since 2×305024431151312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 30502443115092 and 30502443115101.
It is not an unprimeable number, because it can be changed into a prime (30502443115831) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 148758211 + ... + 148963116.
It is an arithmetic number, because the mean of its divisors is an integer number (1425489718464).
Almost surely, 230502443115131 is an apocalyptic number.
30502443115131 is a deficient number, since it is larger than the sum of its proper divisors (15113227875717).
30502443115131 is a wasteful number, since it uses less digits than its factorization.
30502443115131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 297721451.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 30502443115131 its reverse (13151134420503), we get a palindrome (43653577535634).
The spelling of 30502443115131 in words is "thirty trillion, five hundred two billion, four hundred forty-three million, one hundred fifteen thousand, one hundred thirty-one".
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