Base | Representation |
---|---|
bin | 11100011010101111… |
… | …100001111100011011 |
3 | 2220202112102021120112 |
4 | 130122233201330123 |
5 | 444442420012431 |
6 | 22003452514535 |
7 | 2130102643034 |
oct | 343257417433 |
9 | 86675367515 |
10 | 30513438491 |
11 | 11a39049a68 |
12 | 5ab6a7ba4b |
13 | 2b53873b63 |
14 | 16966dba8b |
15 | bd8c48c2b |
hex | 71abe1f1b |
30513438491 has 2 divisors, whose sum is σ = 30513438492. Its totient is φ = 30513438490.
The previous prime is 30513438481. The next prime is 30513438511. The reversal of 30513438491 is 19483431503.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30513438491 is a prime.
It is not a weakly prime, because it can be changed into another prime (30513438481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15256719245 + 15256719246.
It is an arithmetic number, because the mean of its divisors is an integer number (15256719246).
Almost surely, 230513438491 is an apocalyptic number.
30513438491 is a deficient number, since it is larger than the sum of its proper divisors (1).
30513438491 is an equidigital number, since it uses as much as digits as its factorization.
30513438491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 41.
Adding to 30513438491 its reverse (19483431503), we get a palindrome (49996869994).
The spelling of 30513438491 in words is "thirty billion, five hundred thirteen million, four hundred thirty-eight thousand, four hundred ninety-one".
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