Base | Representation |
---|---|
bin | 1101111000000101001100… |
… | …00010011011001001001111 |
3 | 11000001010120101102020210220 |
4 | 12330002212002123021033 |
5 | 12444421122212332421 |
6 | 144522013440002423 |
7 | 6266403101463405 |
oct | 674024602331117 |
9 | 130033511366726 |
10 | 30514233324111 |
11 | 97a5017230629 |
12 | 3509a43000413 |
13 | 14046313201a4 |
14 | 776c7aa61475 |
15 | 37db2a27d3c6 |
hex | 1bc0a609b24f |
30514233324111 has 32 divisors (see below), whose sum is σ = 41989499713728. Its totient is φ = 19698362204160.
The previous prime is 30514233324109. The next prime is 30514233324139. The reversal of 30514233324111 is 11142333241503.
It is not a de Polignac number, because 30514233324111 - 21 = 30514233324109 is a prime.
It is a super-2 number, since 2×305142333241112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30514233324181) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 98541721 + ... + 98850893.
It is an arithmetic number, because the mean of its divisors is an integer number (1312171866054).
Almost surely, 230514233324111 is an apocalyptic number.
30514233324111 is a deficient number, since it is larger than the sum of its proper divisors (11475266389617).
30514233324111 is a wasteful number, since it uses less digits than its factorization.
30514233324111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 315211.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 30514233324111 its reverse (11142333241503), we get a palindrome (41656566565614).
The spelling of 30514233324111 in words is "thirty trillion, five hundred fourteen billion, two hundred thirty-three million, three hundred twenty-four thousand, one hundred eleven".
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