Base | Representation |
---|---|
bin | 1101111000001011101001… |
… | …00111010111100000101011 |
3 | 11000001110111220220200012022 |
4 | 12330011310213113200223 |
5 | 13000000221433140201 |
6 | 144523345403535055 |
7 | 6266555014304231 |
oct | 674056447274053 |
9 | 130043456820168 |
10 | 30517699115051 |
11 | 97a6535612665 |
12 | 350a64b82a48b |
13 | 1404a6436ca65 |
14 | 7770c9076951 |
15 | 37dc7e67e41b |
hex | 1bc1749d782b |
30517699115051 has 2 divisors, whose sum is σ = 30517699115052. Its totient is φ = 30517699115050.
The previous prime is 30517699114951. The next prime is 30517699115089. The reversal of 30517699115051 is 15051199671503.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30517699115051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30517699114984 and 30517699115002.
It is not a weakly prime, because it can be changed into another prime (30517699118051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15258849557525 + 15258849557526.
It is an arithmetic number, because the mean of its divisors is an integer number (15258849557526).
Almost surely, 230517699115051 is an apocalyptic number.
30517699115051 is a deficient number, since it is larger than the sum of its proper divisors (1).
30517699115051 is an equidigital number, since it uses as much as digits as its factorization.
30517699115051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1275750, while the sum is 53.
The spelling of 30517699115051 in words is "thirty trillion, five hundred seventeen billion, six hundred ninety-nine million, one hundred fifteen thousand, fifty-one".
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