Base | Representation |
---|---|
bin | 101100011010110111101… |
… | …010111001001100010001 |
3 | 101210211001112211000002001 |
4 | 230122313222321030101 |
5 | 400003014103124433 |
6 | 10254145233354001 |
7 | 433352000026441 |
oct | 54326752711421 |
9 | 11724045730061 |
10 | 3052508254993 |
11 | a7761a37093a |
12 | 41371aa08901 |
13 | 191b0912c582 |
14 | a7a567c6121 |
15 | 546093e557d |
hex | 2c6b7ab9311 |
3052508254993 has 2 divisors, whose sum is σ = 3052508254994. Its totient is φ = 3052508254992.
The previous prime is 3052508254987. The next prime is 3052508255059. The reversal of 3052508254993 is 3994528052503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3030130488529 + 22377766464 = 1740727^2 + 149592^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3052508254993 is a prime.
It is not a weakly prime, because it can be changed into another prime (3052508254493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526254127496 + 1526254127497.
It is an arithmetic number, because the mean of its divisors is an integer number (1526254127497).
Almost surely, 23052508254993 is an apocalyptic number.
It is an amenable number.
3052508254993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3052508254993 is an equidigital number, since it uses as much as digits as its factorization.
3052508254993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664000, while the sum is 55.
The spelling of 3052508254993 in words is "three trillion, fifty-two billion, five hundred eight million, two hundred fifty-four thousand, nine hundred ninety-three".
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