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30530005050481 is a prime number
BaseRepresentation
bin1101111000100010100100…
…00110110010010001110001
311000002122021112200222001121
412330101102012302101301
513000200422243103411
6144533142442502241
76300501662111056
oct674212206622161
9130078245628047
1030530005050481
11980077aa32032
123510b04b04981
131405c759ccb61
1477793557102d
1537e24ebd2571
hex1bc4521b2471

30530005050481 has 2 divisors, whose sum is σ = 30530005050482. Its totient is φ = 30530005050480.

The previous prime is 30530005050439. The next prime is 30530005050553. The reversal of 30530005050481 is 18405050003503.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26985521068081 + 3544483982400 = 5194759^2 + 1882680^2 .

It is a cyclic number.

It is not a de Polignac number, because 30530005050481 - 225 = 30529971496049 is a prime.

It is a super-3 number, since 3×305300050504813 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (30530005050401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15265002525240 + 15265002525241.

It is an arithmetic number, because the mean of its divisors is an integer number (15265002525241).

Almost surely, 230530005050481 is an apocalyptic number.

It is an amenable number.

30530005050481 is a deficient number, since it is larger than the sum of its proper divisors (1).

30530005050481 is an equidigital number, since it uses as much as digits as its factorization.

30530005050481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 30530005050481 its reverse (18405050003503), we get a palindrome (48935055053984).

The spelling of 30530005050481 in words is "thirty trillion, five hundred thirty billion, five million, fifty thousand, four hundred eighty-one".