Base | Representation |
---|---|
bin | 101100011011101101101… |
… | …001000011100010010001 |
3 | 101210220101122122112202011 |
4 | 230123231221003202101 |
5 | 400011342404231422 |
6 | 10254415141222521 |
7 | 433413303402421 |
oct | 54335551034221 |
9 | 11726348575664 |
10 | 3053413742737 |
11 | a77a44501216 |
12 | 413932101a41 |
13 | 191c218c7a37 |
14 | a7b00b70481 |
15 | 5465db58077 |
hex | 2c6eda43891 |
3053413742737 has 2 divisors, whose sum is σ = 3053413742738. Its totient is φ = 3053413742736.
The previous prime is 3053413742633. The next prime is 3053413742777. The reversal of 3053413742737 is 7372473143503.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2629923863616 + 423489879121 = 1621704^2 + 650761^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3053413742737 is a prime.
It is not a weakly prime, because it can be changed into another prime (3053413742777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526706871368 + 1526706871369.
It is an arithmetic number, because the mean of its divisors is an integer number (1526706871369).
Almost surely, 23053413742737 is an apocalyptic number.
It is an amenable number.
3053413742737 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053413742737 is an equidigital number, since it uses as much as digits as its factorization.
3053413742737 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4445280, while the sum is 49.
The spelling of 3053413742737 in words is "three trillion, fifty-three billion, four hundred thirteen million, seven hundred forty-two thousand, seven hundred thirty-seven".
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