Base | Representation |
---|---|
bin | 101100011011101110001… |
… | …101101100001001001011 |
3 | 101210220102022201110021212 |
4 | 230123232031230021023 |
5 | 400011402334040001 |
6 | 10254420123123335 |
7 | 433413451131125 |
oct | 54335615541113 |
9 | 11726368643255 |
10 | 3053423346251 |
11 | a77a49970503 |
12 | 41393537354b |
13 | 191c238aaca5 |
14 | a7b02150215 |
15 | 5465e9037bb |
hex | 2c6ee36c24b |
3053423346251 has 2 divisors, whose sum is σ = 3053423346252. Its totient is φ = 3053423346250.
The previous prime is 3053423346173. The next prime is 3053423346277. The reversal of 3053423346251 is 1526433243503.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3053423346251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3053423346199 and 3053423346208.
It is not a weakly prime, because it can be changed into another prime (3053423346551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526711673125 + 1526711673126.
It is an arithmetic number, because the mean of its divisors is an integer number (1526711673126).
Almost surely, 23053423346251 is an apocalyptic number.
3053423346251 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053423346251 is an equidigital number, since it uses as much as digits as its factorization.
3053423346251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 41.
Adding to 3053423346251 its reverse (1526433243503), we get a palindrome (4579856589754).
The spelling of 3053423346251 in words is "three trillion, fifty-three billion, four hundred twenty-three million, three hundred forty-six thousand, two hundred fifty-one".
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