Base | Representation |
---|---|
bin | 101100011011101110001… |
… | …111000111100000110001 |
3 | 101210220102100102110122211 |
4 | 230123232033013200301 |
5 | 400011402433023442 |
6 | 10254420135132121 |
7 | 433413454250203 |
oct | 54335617074061 |
9 | 11726370373584 |
10 | 3053423720497 |
11 | a77a4a0a66a7 |
12 | 413935514041 |
13 | 191c239ac437 |
14 | a7b0220a773 |
15 | 5465e979617 |
hex | 2c6ee3c7831 |
3053423720497 has 2 divisors, whose sum is σ = 3053423720498. Its totient is φ = 3053423720496.
The previous prime is 3053423720491. The next prime is 3053423720539. The reversal of 3053423720497 is 7940273243503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2776625675041 + 276798045456 = 1666321^2 + 526116^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3053423720497 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3053423720497.
It is not a weakly prime, because it can be changed into another prime (3053423720491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526711860248 + 1526711860249.
It is an arithmetic number, because the mean of its divisors is an integer number (1526711860249).
Almost surely, 23053423720497 is an apocalyptic number.
It is an amenable number.
3053423720497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053423720497 is an equidigital number, since it uses as much as digits as its factorization.
3053423720497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3810240, while the sum is 49.
The spelling of 3053423720497 in words is "three trillion, fifty-three billion, four hundred twenty-three million, seven hundred twenty thousand, four hundred ninety-seven".
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