Base | Representation |
---|---|
bin | 101100011011110100110… |
… | …011110100011101100011 |
3 | 101210220201000221111200102 |
4 | 230123310303310131203 |
5 | 400012114201130331 |
6 | 10254435115013015 |
7 | 433416263535503 |
oct | 54336463643543 |
9 | 11726630844612 |
10 | 3053534005091 |
11 | a77aa6382099 |
12 | 41396643a16b |
13 | 191c407b41ab |
14 | a7b12b17a03 |
15 | 546694b14cb |
hex | 2c6f4cf4763 |
3053534005091 has 2 divisors, whose sum is σ = 3053534005092. Its totient is φ = 3053534005090.
The previous prime is 3053534005037. The next prime is 3053534005097. The reversal of 3053534005091 is 1905004353503.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3053534005091 - 210 = 3053534004067 is a prime.
It is not a weakly prime, because it can be changed into another prime (3053534005097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526767002545 + 1526767002546.
It is an arithmetic number, because the mean of its divisors is an integer number (1526767002546).
Almost surely, 23053534005091 is an apocalyptic number.
3053534005091 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053534005091 is an equidigital number, since it uses as much as digits as its factorization.
3053534005091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 38.
Adding to 3053534005091 its reverse (1905004353503), we get a palindrome (4958538358594).
The spelling of 3053534005091 in words is "three trillion, fifty-three billion, five hundred thirty-four million, five thousand, ninety-one".
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