Base | Representation |
---|---|
bin | 1101111000110101100111… |
… | …10011010010011100011011 |
3 | 11000010121200102100112021120 |
4 | 12330122303303102130123 |
5 | 13000332344403303430 |
6 | 144541553445340323 |
7 | 6301313320103151 |
oct | 674326363223433 |
9 | 130117612315246 |
10 | 30540234041115 |
11 | 9805049a300a7 |
12 | 3512a9a7076a3 |
13 | 1406c15c85036 |
14 | 778225ca13d1 |
15 | 37e64cc24610 |
hex | 1bc6b3cd271b |
30540234041115 has 16 divisors (see below), whose sum is σ = 49040780156448. Its totient is φ = 16229322925056.
The previous prime is 30540234041101. The next prime is 30540234041143. The reversal of 30540234041115 is 51114043204503.
It is not a de Polignac number, because 30540234041115 - 210 = 30540234040091 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3675114262 + ... + 3675122571.
It is an arithmetic number, because the mean of its divisors is an integer number (3065048759778).
Almost surely, 230540234041115 is an apocalyptic number.
30540234041115 is a deficient number, since it is larger than the sum of its proper divisors (18500546115333).
30540234041115 is a wasteful number, since it uses less digits than its factorization.
30540234041115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7350237118.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 30540234041115 its reverse (51114043204503), we get a palindrome (81654277245618).
The spelling of 30540234041115 in words is "thirty trillion, five hundred forty billion, two hundred thirty-four million, forty-one thousand, one hundred fifteen".
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