Base | Representation |
---|---|
bin | 101100011100110011110… |
… | …001100100101011001011 |
3 | 101211000102122200221122201 |
4 | 230130303301210223023 |
5 | 400021300114140442 |
6 | 10255132012501031 |
7 | 433454411560063 |
oct | 54346361445313 |
9 | 11730378627581 |
10 | 3054590380747 |
11 | a78498700824 |
12 | 41400017a777 |
13 | 19207b5cc749 |
14 | a7bb313c3a3 |
15 | 546cc0cb7b7 |
hex | 2c733c64acb |
3054590380747 has 2 divisors, whose sum is σ = 3054590380748. Its totient is φ = 3054590380746.
The previous prime is 3054590380739. The next prime is 3054590380861. The reversal of 3054590380747 is 7470830954503.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3054590380747 - 23 = 3054590380739 is a prime.
It is not a weakly prime, because it can be changed into another prime (3054590380147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527295190373 + 1527295190374.
It is an arithmetic number, because the mean of its divisors is an integer number (1527295190374).
Almost surely, 23054590380747 is an apocalyptic number.
3054590380747 is a deficient number, since it is larger than the sum of its proper divisors (1).
3054590380747 is an equidigital number, since it uses as much as digits as its factorization.
3054590380747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12700800, while the sum is 55.
The spelling of 3054590380747 in words is "three trillion, fifty-four billion, five hundred ninety million, three hundred eighty thousand, seven hundred forty-seven".
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