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30550251102025 = 521222010044081
BaseRepresentation
bin1101111001001000010001…
…10111010101111101001001
311000011120112112012221120111
412330210020313111331021
513001013403240231100
6144550331441554321
76302116462523314
oct674441067257511
9130146475187514
1030550251102025
11980931a338236
123514a153459a1
131407b51366c05
147788d63c597b
1537ea373526ba
hex1bc908dd5f49

30550251102025 has 6 divisors (see below), whose sum is σ = 37882311366542. Its totient is φ = 24440200881600.

The previous prime is 30550251101957. The next prime is 30550251102053. The reversal of 30550251102025 is 52020115205503.

It can be written as a sum of positive squares in 3 ways, for example, as 578042404681 + 29972208697344 = 760291^2 + 5474688^2 .

It is a de Polignac number, because none of the positive numbers 2k-30550251102025 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 611005022016 + ... + 611005022065.

Almost surely, 230550251102025 is an apocalyptic number.

It is an amenable number.

30550251102025 is a deficient number, since it is larger than the sum of its proper divisors (7332060264517).

30550251102025 is a wasteful number, since it uses less digits than its factorization.

30550251102025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1222010044091 (or 1222010044086 counting only the distinct ones).

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 30550251102025 its reverse (52020115205503), we get a palindrome (82570366307528).

The spelling of 30550251102025 in words is "thirty trillion, five hundred fifty billion, two hundred fifty-one million, one hundred two thousand, twenty-five".

Divisors: 1 5 25 1222010044081 6110050220405 30550251102025