Base | Representation |
---|---|
bin | 101100011101001110110… |
… | …101001001100010011001 |
3 | 101211001121021211120221001 |
4 | 230131032311021202121 |
5 | 400023212320144001 |
6 | 10255245025545001 |
7 | 433501563053425 |
oct | 54351665114231 |
9 | 11731537746831 |
10 | 3055044303001 |
11 | a78700956289 |
12 | 4141081a5161 |
13 | 1921216707b2 |
14 | a7c1753bb85 |
15 | 54706d92001 |
hex | 2c74ed49899 |
3055044303001 has 2 divisors, whose sum is σ = 3055044303002. Its totient is φ = 3055044303000.
The previous prime is 3055044302993. The next prime is 3055044303121. The reversal of 3055044303001 is 1003034405503.
3055044303001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2312069261401 + 742975041600 = 1520549^2 + 861960^2 .
It is a cyclic number.
It is not a de Polignac number, because 3055044303001 - 23 = 3055044302993 is a prime.
It is not a weakly prime, because it can be changed into another prime (3055044303601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527522151500 + 1527522151501.
It is an arithmetic number, because the mean of its divisors is an integer number (1527522151501).
Almost surely, 23055044303001 is an apocalyptic number.
It is an amenable number.
3055044303001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3055044303001 is an equidigital number, since it uses as much as digits as its factorization.
3055044303001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 3055044303001 its reverse (1003034405503), we get a palindrome (4058078708504).
The spelling of 3055044303001 in words is "three trillion, fifty-five billion, forty-four million, three hundred three thousand, one".
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