Base | Representation |
---|---|
bin | 101100011101001111001… |
… | …101000001011100110011 |
3 | 101211001121201121112202001 |
4 | 230131033031001130303 |
5 | 400023220420430311 |
6 | 10255245412034431 |
7 | 433502000210326 |
oct | 54351715013463 |
9 | 11731551545661 |
10 | 3055050561331 |
11 | a7870444025a |
12 | 41410a302a17 |
13 | 192122a52252 |
14 | a7c182ca7bd |
15 | 547076cb4c1 |
hex | 2c74f341733 |
3055050561331 has 8 divisors (see below), whose sum is σ = 3123842747904. Its totient is φ = 2986416337800.
The previous prime is 3055050561301. The next prime is 3055050561377. The reversal of 3055050561331 is 1331650505503.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3055050561331 - 217 = 3055050430259 is a prime.
It is a super-4 number, since 4×30550505613314 (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3055050561301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39451645 + ... + 39529006.
It is an arithmetic number, because the mean of its divisors is an integer number (390480343488).
Almost surely, 23055050561331 is an apocalyptic number.
3055050561331 is a deficient number, since it is larger than the sum of its proper divisors (68792186573).
3055050561331 is an equidigital number, since it uses as much as digits as its factorization.
3055050561331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78981521.
The product of its (nonzero) digits is 101250, while the sum is 37.
The spelling of 3055050561331 in words is "three trillion, fifty-five billion, fifty million, five hundred sixty-one thousand, three hundred thirty-one".
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