Base | Representation |
---|---|
bin | 101101000111000110011… |
… | …010110100110111111001 |
3 | 101222100122100112222010212 |
4 | 231013012122310313321 |
5 | 401242300041411442 |
6 | 10332042005520505 |
7 | 436652620064153 |
oct | 55070632646771 |
9 | 11870570488125 |
10 | 3100000341497 |
11 | a95780415404 |
12 | 420973a13135 |
13 | 19643742bbc7 |
14 | aa080005ad3 |
15 | 559889e9a82 |
hex | 2d1c66b4df9 |
3100000341497 has 4 divisors (see below), whose sum is σ = 3100007612160. Its totient is φ = 3099993070836.
The previous prime is 3100000341467. The next prime is 3100000341541. The reversal of 3100000341497 is 7941430000013.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3100000341497 - 226 = 3099933232633 is a prime.
It is a super-2 number, since 2×31000003414972 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3100000341467) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2953097 + ... + 3862742.
It is an arithmetic number, because the mean of its divisors is an integer number (775001903040).
Almost surely, 23100000341497 is an apocalyptic number.
It is an amenable number.
3100000341497 is a deficient number, since it is larger than the sum of its proper divisors (7270663).
3100000341497 is an equidigital number, since it uses as much as digits as its factorization.
3100000341497 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7270662.
The product of its (nonzero) digits is 9072, while the sum is 32.
The spelling of 3100000341497 in words is "three trillion, one hundred billion, three hundred forty-one thousand, four hundred ninety-seven".
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