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31001132013 = 3191134813093
BaseRepresentation
bin11100110111110011…
…111011101111101101
32222000112002200022120
4130313303323233231
51001442242211023
622124113503153
72145144163035
oct346763735755
988015080276
1031001132013
1112169370365
126012271ab9
132c0090a5c7
1417013ac8c5
15c169808e3
hex737cfbbed

31001132013 has 16 divisors (see below), whose sum is σ = 43895417280. Its totient is φ = 19406386944.

The previous prime is 31001132009. The next prime is 31001132069. The reversal of 31001132013 is 31023110013.

It is not a de Polignac number, because 31001132013 - 22 = 31001132009 is a prime.

It is a super-2 number, since 2×310011320132 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31001131983 and 31001132001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31001132083) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2400106 + ... + 2412987.

It is an arithmetic number, because the mean of its divisors is an integer number (2743463580).

Almost surely, 231001132013 is an apocalyptic number.

It is an amenable number.

31001132013 is a deficient number, since it is larger than the sum of its proper divisors (12894285267).

31001132013 is a wasteful number, since it uses less digits than its factorization.

31001132013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4813228.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 31001132013 its reverse (31023110013), we get a palindrome (62024242026).

The spelling of 31001132013 in words is "thirty-one billion, one million, one hundred thirty-two thousand, thirteen".

Divisors: 1 3 19 57 113 339 2147 6441 4813093 14439279 91448767 274346301 543879509 1631638527 10333710671 31001132013