Base | Representation |
---|---|
bin | 11100110111110100… |
… | …000000011010111001 |
3 | 2222000112010122120202 |
4 | 130313310000122321 |
5 | 1001442243314121 |
6 | 22124114131545 |
7 | 2145144302621 |
oct | 346764003271 |
9 | 88015118522 |
10 | 31001151161 |
11 | 12169383792 |
12 | 6012280bb5 |
13 | 2c00916236 |
14 | 17013b5881 |
15 | c1698640b |
hex | 737d006b9 |
31001151161 has 2 divisors, whose sum is σ = 31001151162. Its totient is φ = 31001151160.
The previous prime is 31001151067. The next prime is 31001151217. The reversal of 31001151161 is 16115110013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30833604025 + 167547136 = 175595^2 + 12944^2 .
It is an emirp because it is prime and its reverse (16115110013) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31001151161 - 210 = 31001150137 is a prime.
It is a super-2 number, since 2×310011511612 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31001150161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15500575580 + 15500575581.
It is an arithmetic number, because the mean of its divisors is an integer number (15500575581).
Almost surely, 231001151161 is an apocalyptic number.
It is an amenable number.
31001151161 is a deficient number, since it is larger than the sum of its proper divisors (1).
31001151161 is an equidigital number, since it uses as much as digits as its factorization.
31001151161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 31001151161 its reverse (16115110013), we get a palindrome (47116261174).
The spelling of 31001151161 in words is "thirty-one billion, one million, one hundred fifty-one thousand, one hundred sixty-one".
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