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310031041114 = 2318817486221
BaseRepresentation
bin1001000001011110100…
…10100100001001011010
31002122020121002201021101
410200233102210021122
520034420421303424
6354232025102014
731253600240224
oct4405722441132
91078217081241
10310031041114
1110a535492a23
125010492790a
132330b096bb2
1411011465414
1580e814e344
hex482f4a425a

310031041114 has 8 divisors (see below), whose sum is σ = 465048976788. Its totient is φ = 155014715520.

The previous prime is 310031041093. The next prime is 310031041129. The reversal of 310031041114 is 411140130013.

It can be written as a sum of positive squares in 2 ways, for example, as 240958265625 + 69072775489 = 490875^2 + 262817^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×3100310411142 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 310031041091 and 310031041100.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394524 + ... + 880744.

Almost surely, 2310031041114 is an apocalyptic number.

310031041114 is a deficient number, since it is larger than the sum of its proper divisors (155017935674).

310031041114 is a wasteful number, since it uses less digits than its factorization.

310031041114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 805040.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 310031041114 its reverse (411140130013), we get a palindrome (721171171127).

The spelling of 310031041114 in words is "three hundred ten billion, thirty-one million, forty-one thousand, one hundred fourteen".

Divisors: 1 2 318817 486221 637634 972442 155015520557 310031041114