Base | Representation |
---|---|
bin | 11100110111111111… |
… | …011010010111110001 |
3 | 2222000201202112221001 |
4 | 130313333122113301 |
5 | 1001444030003131 |
6 | 22124302202001 |
7 | 2145211564516 |
oct | 346777322761 |
9 | 88021675831 |
10 | 31004141041 |
11 | 12170036065 |
12 | 6013283301 |
13 | 2c014220b3 |
14 | 170195330d |
15 | c16d77261 |
hex | 737fda5f1 |
31004141041 has 4 divisors (see below), whose sum is σ = 31004587584. Its totient is φ = 31003694500.
The previous prime is 31004140997. The next prime is 31004141087. The reversal of 31004141041 is 14014140013.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14014140013 = 41 ⋅341808293.
It is a cyclic number.
It is not a de Polignac number, because 31004141041 - 27 = 31004140913 is a prime.
It is a super-2 number, since 2×310041410412 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31004141341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94285 + ... + 266266.
It is an arithmetic number, because the mean of its divisors is an integer number (7751146896).
Almost surely, 231004141041 is an apocalyptic number.
It is an amenable number.
31004141041 is a deficient number, since it is larger than the sum of its proper divisors (446543).
31004141041 is an equidigital number, since it uses as much as digits as its factorization.
31004141041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 446542.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 31004141041 its reverse (14014140013), we get a palindrome (45018281054).
The spelling of 31004141041 in words is "thirty-one billion, four million, one hundred forty-one thousand, forty-one".
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