Base | Representation |
---|---|
bin | 100011010001000101110001… |
… | …0110011001110011101101011 |
3 | 1111200100222200112012200210121 |
4 | 1012202023202303032131223 |
5 | 311130003401412002144 |
6 | 3015433251035024111 |
7 | 122225041226654146 |
oct | 10642134263163553 |
9 | 1450328615180717 |
10 | 310212113000299 |
11 | 8a930244637094 |
12 | 2a961228b9b037 |
13 | 10412b52259bb3 |
14 | 56864bc67b05d |
15 | 25ce4e0368384 |
hex | 11a22e2cce76b |
310212113000299 has 4 divisors (see below), whose sum is σ = 313949608337736. Its totient is φ = 306474617662864.
The previous prime is 310212113000291. The next prime is 310212113000477. The reversal of 310212113000299 is 992000311212013.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 310212113000299 - 23 = 310212113000291 is a prime.
It is a super-2 number, since 2×3102121130002992 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (310212113000291) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1868747668594 + ... + 1868747668759.
It is an arithmetic number, because the mean of its divisors is an integer number (78487402084434).
Almost surely, 2310212113000299 is an apocalyptic number.
310212113000299 is a deficient number, since it is larger than the sum of its proper divisors (3737495337437).
310212113000299 is an equidigital number, since it uses as much as digits as its factorization.
310212113000299 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3737495337436.
The product of its (nonzero) digits is 5832, while the sum is 34.
The spelling of 310212113000299 in words is "three hundred ten trillion, two hundred twelve billion, one hundred thirteen million, two hundred ninety-nine", and thus it is an aban number.
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