Base | Representation |
---|---|
bin | 1110000110110111101111… |
… | …01111001001001011101001 |
3 | 11001211201021002202101002202 |
4 | 13003123313233021023221 |
5 | 13031232343444024231 |
6 | 145551255400505545 |
7 | 6351203146250414 |
oct | 703336757111351 |
9 | 131751232671082 |
10 | 31022410142441 |
11 | 9980591855723 |
12 | 359042647b2b5 |
13 | 144052950c9b3 |
14 | 7936c7c18b7b |
15 | 38be6db875cb |
hex | 1c36f7bc92e9 |
31022410142441 has 2 divisors, whose sum is σ = 31022410142442. Its totient is φ = 31022410142440.
The previous prime is 31022410142411. The next prime is 31022410142459. The reversal of 31022410142441 is 14424101422013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20170518145600 + 10851891996841 = 4491160^2 + 3294221^2 .
It is a cyclic number.
It is not a de Polignac number, because 31022410142441 - 210 = 31022410141417 is a prime.
It is not a weakly prime, because it can be changed into another prime (31022410142411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15511205071220 + 15511205071221.
It is an arithmetic number, because the mean of its divisors is an integer number (15511205071221).
Almost surely, 231022410142441 is an apocalyptic number.
It is an amenable number.
31022410142441 is a deficient number, since it is larger than the sum of its proper divisors (1).
31022410142441 is an equidigital number, since it uses as much as digits as its factorization.
31022410142441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 31022410142441 its reverse (14424101422013), we get a palindrome (45446511564454).
The spelling of 31022410142441 in words is "thirty-one trillion, twenty-two billion, four hundred ten million, one hundred forty-two thousand, four hundred forty-one".
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