Base | Representation |
---|---|
bin | 1001000010001100000… |
… | …00010100001100000001 |
3 | 1002200020011012012020011 |
4 | 10201012000110030001 |
5 | 20041211001224441 |
6 | 354333521144521 |
7 | 31266205411516 |
oct | 4410600241401 |
9 | 1080204165204 |
10 | 310412133121 |
11 | 10a710613aa2 |
12 | 501b048b141 |
13 | 2336c01811c |
14 | 11049d0730d |
15 | 811b82a581 |
hex | 4846014301 |
310412133121 has 2 divisors, whose sum is σ = 310412133122. Its totient is φ = 310412133120.
The previous prime is 310412133071. The next prime is 310412133139. The reversal of 310412133121 is 121331214013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 302429604096 + 7982529025 = 549936^2 + 89345^2 .
It is a cyclic number.
It is not a de Polignac number, because 310412133121 - 215 = 310412100353 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 310412133092 and 310412133101.
It is not a weakly prime, because it can be changed into another prime (310412133221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155206066560 + 155206066561.
It is an arithmetic number, because the mean of its divisors is an integer number (155206066561).
Almost surely, 2310412133121 is an apocalyptic number.
It is an amenable number.
310412133121 is a deficient number, since it is larger than the sum of its proper divisors (1).
310412133121 is an equidigital number, since it uses as much as digits as its factorization.
310412133121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 310412133121 its reverse (121331214013), we get a palindrome (431743347134).
The spelling of 310412133121 in words is "three hundred ten billion, four hundred twelve million, one hundred thirty-three thousand, one hundred twenty-one".
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