Base | Representation |
---|---|
bin | 111011001110… |
… | …0100110000001 |
3 | 2011102111202012 |
4 | 1312130212001 |
5 | 30422100423 |
6 | 3025302305 |
7 | 524631053 |
oct | 166344601 |
9 | 64374665 |
10 | 31050113 |
11 | 16588456 |
12 | a494995 |
13 | 6581c63 |
14 | 41a38d3 |
15 | 2ad5078 |
hex | 1d9c981 |
31050113 has 2 divisors, whose sum is σ = 31050114. Its totient is φ = 31050112.
The previous prime is 31050083. The next prime is 31050121. The reversal of 31050113 is 31105013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29246464 + 1803649 = 5408^2 + 1343^2 .
It is an emirp because it is prime and its reverse (31105013) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31050113 - 212 = 31046017 is a prime.
It is not a weakly prime, because it can be changed into another prime (31010113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15525056 + 15525057.
It is an arithmetic number, because the mean of its divisors is an integer number (15525057).
Almost surely, 231050113 is an apocalyptic number.
It is an amenable number.
31050113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31050113 is an equidigital number, since it uses as much as digits as its factorization.
31050113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 14.
The square root of 31050113 is about 5572.2628258186. The cubic root of 31050113 is about 314.3072472358.
Adding to 31050113 its reverse (31105013), we get a palindrome (62155126).
The spelling of 31050113 in words is "thirty-one million, fifty thousand, one hundred thirteen".
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