Base | Representation |
---|---|
bin | 1110001001001000100000… |
… | …10101010101110100110011 |
3 | 11002010010212200120000020201 |
4 | 13010210100111111310303 |
5 | 13034021032322021321 |
6 | 150051111542420031 |
7 | 6356624161102345 |
oct | 704442025256463 |
9 | 132103780500221 |
10 | 31100132220211 |
11 | 9a0054595004a |
12 | 35a34b7431617 |
13 | 144796472c722 |
14 | 79737c231295 |
15 | 38debc196291 |
hex | 1c4910555d33 |
31100132220211 has 2 divisors, whose sum is σ = 31100132220212. Its totient is φ = 31100132220210.
The previous prime is 31100132220191. The next prime is 31100132220253. The reversal of 31100132220211 is 11202223100113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31100132220211 - 29 = 31100132219699 is a prime.
It is a super-2 number, since 2×311001322202112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31100132220271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550066110105 + 15550066110106.
It is an arithmetic number, because the mean of its divisors is an integer number (15550066110106).
Almost surely, 231100132220211 is an apocalyptic number.
31100132220211 is a deficient number, since it is larger than the sum of its proper divisors (1).
31100132220211 is an equidigital number, since it uses as much as digits as its factorization.
31100132220211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31100132220211 its reverse (11202223100113), we get a palindrome (42302355320324).
The spelling of 31100132220211 in words is "thirty-one trillion, one hundred billion, one hundred thirty-two million, two hundred twenty thousand, two hundred eleven".
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