Base | Representation |
---|---|
bin | 101101010000011011101… |
… | …001010001000010010011 |
3 | 102000022111122112200212212 |
4 | 231100123221101002103 |
5 | 401423310122443234 |
6 | 10340420140342335 |
7 | 440456124613346 |
oct | 55203351210223 |
9 | 12008448480785 |
10 | 3110020124819 |
11 | a99a52311973 |
12 | 4228ab5449ab |
13 | 197373254c8a |
14 | aa750a3845d |
15 | 55d734b45ce |
hex | 2d41ba51093 |
3110020124819 has 2 divisors, whose sum is σ = 3110020124820. Its totient is φ = 3110020124818.
The previous prime is 3110020124803. The next prime is 3110020124881. The reversal of 3110020124819 is 9184210200113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3110020124819 - 24 = 3110020124803 is a prime.
It is a super-3 number, since 3×31100201248193 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3110020124899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555010062409 + 1555010062410.
It is an arithmetic number, because the mean of its divisors is an integer number (1555010062410).
Almost surely, 23110020124819 is an apocalyptic number.
3110020124819 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110020124819 is an equidigital number, since it uses as much as digits as its factorization.
3110020124819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 32.
The spelling of 3110020124819 in words is "three trillion, one hundred ten billion, twenty million, one hundred twenty-four thousand, eight hundred nineteen".
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