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311003232220019 is a prime number
BaseRepresentation
bin100011010110110110001010…
…1001011100011001101110011
31111210011121200222121001111002
41012231230111023203031303
5311230434104422020034
63021240525033312215
7122336146006246403
oct10655542513431563
91453147628531432
10311003232220019
1190105803829149
122aa6a61526566b
131046c62c368ca1
1456b28cb382803
1525e4d93b7ce7e
hex11adb152e3373

311003232220019 has 2 divisors, whose sum is σ = 311003232220020. Its totient is φ = 311003232220018.

The previous prime is 311003232220007. The next prime is 311003232220091. The reversal of 311003232220019 is 910022232300113.

Together with next prime (311003232220091) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311003232220019 is a prime.

It is a super-2 number, since 2×3110032322200192 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311003232219973 and 311003232220000.

It is not a weakly prime, because it can be changed into another prime (311093232220019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155501616110009 + 155501616110010.

It is an arithmetic number, because the mean of its divisors is an integer number (155501616110010).

Almost surely, 2311003232220019 is an apocalyptic number.

311003232220019 is a deficient number, since it is larger than the sum of its proper divisors (1).

311003232220019 is an equidigital number, since it uses as much as digits as its factorization.

311003232220019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 311003232220019 in words is "three hundred eleven trillion, three billion, two hundred thirty-two million, two hundred twenty thousand, nineteen".