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311005343323 = 24125354683
BaseRepresentation
bin1001000011010010101…
…11001110111001011011
31002201202111102101122101
410201221113032321123
520043414331441243
6354512431504231
731320000541363
oct4415127167133
91081674371571
10311005343323
1110a995454664
1250337088077
1323434ba738c
14110a4a039a3
15815395654d
hex48695cee5b

311005343323 has 6 divisors (see below), whose sum is σ = 312301234932. Its totient is φ = 309714806880.

The previous prime is 311005343321. The next prime is 311005343393. The reversal of 311005343323 is 323343500113.

It is not a de Polignac number, because 311005343323 - 21 = 311005343321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311005343291 and 311005343300.

It is not an unprimeable number, because it can be changed into a prime (311005343321) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2619261 + ... + 2735422.

It is an arithmetic number, because the mean of its divisors is an integer number (52050205822).

Almost surely, 2311005343323 is an apocalyptic number.

311005343323 is a deficient number, since it is larger than the sum of its proper divisors (1295891609).

311005343323 is an frugal number, since it uses more digits than its factorization.

311005343323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5355165 (or 5354924 counting only the distinct ones).

The product of its (nonzero) digits is 9720, while the sum is 28.

Adding to 311005343323 its reverse (323343500113), we get a palindrome (634348843436).

The spelling of 311005343323 in words is "three hundred eleven billion, five million, three hundred forty-three thousand, three hundred twenty-three".

Divisors: 1 241 58081 5354683 1290478603 311005343323