311023113 has 4 divisors (see below), whose sum is σ = 414697488. Its totient is φ = 207348740.

The previous prime is 311023099. The next prime is 311023151. The reversal of 311023113 is 311320113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311023113 - 2⁸ = 311022857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311023092 and 311023101.

It is not an unprimeable number, because it can be changed into a prime (311023913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51837183 + ... + 51837188.

It is an arithmetic number, because the mean of its divisors is an integer number (103674372).

Almost surely, 2^311023113 is an apocalyptic number.

It is an amenable number.

311023113 is a deficient number, since it is larger than the sum of its proper divisors (103674375).

311023113 is a wasteful number, since it uses less digits than its factorization.

311023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103674374.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 311023113 is about 17635.8473853682. The cubic root of 311023113 is about 677.5336787858.

Adding to 311023113 its reverse (311320113), we get a palindrome (622343226).

The spelling of 311023113 in words is "three hundred eleven million, twenty-three thousand, one hundred thirteen".