Base | Representation |
---|---|
bin | 100011010110111111011110… |
… | …0000101100101110101010011 |
3 | 1111210020112021102200101222000 |
4 | 1012231332330011211311103 |
5 | 311231301014323302011 |
6 | 3021254031412245043 |
7 | 122340454100311101 |
oct | 10655767405456523 |
9 | 1453215242611860 |
10 | 311023212322131 |
11 | 90113226aa7631 |
12 | 2aa72470610783 |
13 | 10471494897b0a |
14 | 56b3864b68c71 |
15 | 25e5662cb8356 |
hex | 11adfbc165d53 |
311023212322131 has 64 divisors (see below), whose sum is σ = 488655686615040. Its totient is φ = 195172247468160.
The previous prime is 311023212322111. The next prime is 311023212322139. The reversal of 311023212322131 is 131223212320113.
311023212322131 is a `hidden beast` number, since 3 + 1 + 1 + 0 + 2 + 321 + 2 + 322 + 13 + 1 = 666.
It is not a de Polignac number, because 311023212322131 - 25 = 311023212322099 is a prime.
It is a super-2 number, since 2×3110232123221312 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 311023212322095 and 311023212322104.
It is not an unprimeable number, because it can be changed into a prime (311023212322139) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 91958181 + ... + 95280393.
It is an arithmetic number, because the mean of its divisors is an integer number (7635245103360).
Almost surely, 2311023212322131 is an apocalyptic number.
311023212322131 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
311023212322131 is a deficient number, since it is larger than the sum of its proper divisors (177632474292909).
311023212322131 is a wasteful number, since it uses less digits than its factorization.
311023212322131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3325313 (or 3325307 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 311023212322131 its reverse (131223212320113), we get a palindrome (442246424642244).
The spelling of 311023212322131 in words is "three hundred eleven trillion, twenty-three billion, two hundred twelve million, three hundred twenty-two thousand, one hundred thirty-one".
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