Base | Representation |
---|---|
bin | 11100111101110110… |
… | …010101000110010001 |
3 | 2222021120200211000221 |
4 | 130331312111012101 |
5 | 1002144210022231 |
6 | 22142132513041 |
7 | 2150514144235 |
oct | 347566250621 |
9 | 88246624027 |
10 | 31102423441 |
11 | 12210564091 |
12 | 604017b781 |
13 | 2c188b3b6b |
14 | 1710a185c5 |
15 | c207dcd11 |
hex | 73dd95191 |
31102423441 has 2 divisors, whose sum is σ = 31102423442. Its totient is φ = 31102423440.
The previous prime is 31102423433. The next prime is 31102423501. The reversal of 31102423441 is 14432420113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30833955216 + 268468225 = 175596^2 + 16385^2 .
It is a cyclic number.
It is not a de Polignac number, because 31102423441 - 23 = 31102423433 is a prime.
It is not a weakly prime, because it can be changed into another prime (31102426441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551211720 + 15551211721.
It is an arithmetic number, because the mean of its divisors is an integer number (15551211721).
Almost surely, 231102423441 is an apocalyptic number.
It is an amenable number.
31102423441 is a deficient number, since it is larger than the sum of its proper divisors (1).
31102423441 is an equidigital number, since it uses as much as digits as its factorization.
31102423441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 31102423441 its reverse (14432420113), we get a palindrome (45534843554).
The spelling of 31102423441 in words is "thirty-one billion, one hundred two million, four hundred twenty-three thousand, four hundred forty-one".
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