Base | Representation |
---|---|
bin | 1001000011010111000… |
… | …11100100010101111011 |
3 | 1002201212001122102021220 |
4 | 10201223203210111323 |
5 | 20044003241200243 |
6 | 354520224203123 |
7 | 31320625331130 |
oct | 4415343442573 |
9 | 1081761572256 |
10 | 311042131323 |
11 | 10aa041a0a70 |
12 | 503474694a3 |
13 | 2343c6b7c21 |
14 | 110a985c587 |
15 | 8156cc1783 |
hex | 486b8e457b |
311042131323 has 32 divisors (see below), whose sum is σ = 517299374592. Its totient is φ = 161504601600.
The previous prime is 311042131297. The next prime is 311042131343. The reversal of 311042131323 is 323131240113.
It is not a de Polignac number, because 311042131323 - 28 = 311042131067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311042131293 and 311042131302.
It is not an unprimeable number, because it can be changed into a prime (311042131343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 180115 + ... + 809027.
It is an arithmetic number, because the mean of its divisors is an integer number (16165605456).
Almost surely, 2311042131323 is an apocalyptic number.
311042131323 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
311042131323 is a deficient number, since it is larger than the sum of its proper divisors (206257243269).
311042131323 is a wasteful number, since it uses less digits than its factorization.
311042131323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 631075.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 311042131323 its reverse (323131240113), we get a palindrome (634173371436).
The spelling of 311042131323 in words is "three hundred eleven billion, forty-two million, one hundred thirty-one thousand, three hundred twenty-three".
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