311044312153 has 4 divisors (see below), whose sum is σ = 311045964048. Its totient is φ = 311042660260.

The previous prime is 311044312151. The next prime is 311044312177. The reversal of 311044312153 is 351213440113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351213440113 = 19273 ⋅18223081.

It is a cyclic number.

It is not a de Polignac number, because 311044312153 - 2¹ = 311044312151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311044312151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500851 + ... + 934312.

It is an arithmetic number, because the mean of its divisors is an integer number (77761491012).

Almost surely, 2^311044312153 is an apocalyptic number.

It is an amenable number.

311044312153 is a deficient number, since it is larger than the sum of its proper divisors (1651895).

311044312153 is a wasteful number, since it uses less digits than its factorization.

311044312153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1651894.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 311044312153 its reverse (351213440113), we get a palindrome (662257752266).

The spelling of 311044312153 in words is "three hundred eleven billion, forty-four million, three hundred twelve thousand, one hundred fifty-three".