Base | Representation |
---|---|
bin | 1001000011011010001… |
… | …11100000100011010001 |
3 | 1002201220212221110101102 |
4 | 10201231013200203101 |
5 | 20044031443031233 |
6 | 354523001514145 |
7 | 31321364115515 |
oct | 4415507404321 |
9 | 1081825843342 |
10 | 311068330193 |
11 | 10aa17a65625 |
12 | 503541a2955 |
13 | 23444c5ba0a |
14 | 110ad11c145 |
15 | 81592491e8 |
hex | 486d1e08d1 |
311068330193 has 2 divisors, whose sum is σ = 311068330194. Its totient is φ = 311068330192.
The previous prime is 311068330187. The next prime is 311068330211. The reversal of 311068330193 is 391033860113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 243534354064 + 67533976129 = 493492^2 + 259873^2 .
It is a cyclic number.
It is not a de Polignac number, because 311068330193 - 26 = 311068330129 is a prime.
It is a super-2 number, since 2×3110683301932 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311068330493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155534165096 + 155534165097.
It is an arithmetic number, because the mean of its divisors is an integer number (155534165097).
Almost surely, 2311068330193 is an apocalyptic number.
It is an amenable number.
311068330193 is a deficient number, since it is larger than the sum of its proper divisors (1).
311068330193 is an equidigital number, since it uses as much as digits as its factorization.
311068330193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 38.
The spelling of 311068330193 in words is "three hundred eleven billion, sixty-eight million, three hundred thirty thousand, one hundred ninety-three".
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