Base | Representation |
---|---|
bin | 11100111110010011… |
… | …100111010011100001 |
3 | 2222022010010211120002 |
4 | 130332103213103201 |
5 | 1002203141201233 |
6 | 22143005225345 |
7 | 2150636326364 |
oct | 347623472341 |
9 | 88263124502 |
10 | 31110100193 |
11 | 12214927807 |
12 | 6042862255 |
13 | 2c1a371113 |
14 | 1711a560db |
15 | c213076e8 |
hex | 73e4e74e1 |
31110100193 has 2 divisors, whose sum is σ = 31110100194. Its totient is φ = 31110100192.
The previous prime is 31110100169. The next prime is 31110100279. The reversal of 31110100193 is 39100101113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23491079824 + 7619020369 = 153268^2 + 87287^2 .
It is an emirp because it is prime and its reverse (39100101113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31110100193 - 218 = 31109838049 is a prime.
It is not a weakly prime, because it can be changed into another prime (31110100123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555050096 + 15555050097.
It is an arithmetic number, because the mean of its divisors is an integer number (15555050097).
Almost surely, 231110100193 is an apocalyptic number.
It is an amenable number.
31110100193 is a deficient number, since it is larger than the sum of its proper divisors (1).
31110100193 is an equidigital number, since it uses as much as digits as its factorization.
31110100193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 20.
The spelling of 31110100193 in words is "thirty-one billion, one hundred ten million, one hundred thousand, one hundred ninety-three".
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