Base | Representation |
---|---|
bin | 100011010111100011101111… |
… | …1110100110101100000111001 |
3 | 1111210111222101001012121200021 |
4 | 1012233013133310311200321 |
5 | 311234040044024233032 |
6 | 3021353514312410441 |
7 | 122346212542005406 |
oct | 10657073764654071 |
9 | 1453458331177607 |
10 | 311101121321017 |
11 | 90143276661615 |
12 | 2aa855940a6a21 |
13 | 1047892c742a61 |
14 | 56b7535d1b2ad |
15 | 25e76c28eb097 |
hex | 11af1dfd35839 |
311101121321017 has 2 divisors, whose sum is σ = 311101121321018. Its totient is φ = 311101121321016.
The previous prime is 311101121320991. The next prime is 311101121321027. The reversal of 311101121321017 is 710123121101113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 219736122603001 + 91364998718016 = 14823499^2 + 9558504^2 .
It is a cyclic number.
It is not a de Polignac number, because 311101121321017 - 235 = 311066761582649 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311101121320982 and 311101121321000.
It is not a weakly prime, because it can be changed into another prime (311101121321027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155550560660508 + 155550560660509.
It is an arithmetic number, because the mean of its divisors is an integer number (155550560660509).
Almost surely, 2311101121321017 is an apocalyptic number.
It is an amenable number.
311101121321017 is a deficient number, since it is larger than the sum of its proper divisors (1).
311101121321017 is an equidigital number, since it uses as much as digits as its factorization.
311101121321017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
The spelling of 311101121321017 in words is "three hundred eleven trillion, one hundred one billion, one hundred twenty-one million, three hundred twenty-one thousand, seventeen".
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