Base | Representation |
---|---|
bin | 1110001001011011000110… |
… | …10000001000111101100011 |
3 | 11002011002122021201102011111 |
4 | 13010231203100020331203 |
5 | 13034202003001102243 |
6 | 150055442211524151 |
7 | 6360426415634311 |
oct | 704554320107543 |
9 | 132132567642144 |
10 | 31110113300323 |
11 | 9a047a7a12292 |
12 | 35a5421bb9657 |
13 | 14488955242a5 |
14 | 797a47a6b0b1 |
15 | 38e3a356839d |
hex | 1c4b63408f63 |
31110113300323 has 4 divisors (see below), whose sum is σ = 31385424037608. Its totient is φ = 30834802563040.
The previous prime is 31110113300311. The next prime is 31110113300339. The reversal of 31110113300323 is 32300331101113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31110113300323 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31110113300294 and 31110113300303.
It is not an unprimeable number, because it can be changed into a prime (31110113100323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137655368473 + ... + 137655368698.
It is an arithmetic number, because the mean of its divisors is an integer number (7846356009402).
Almost surely, 231110113300323 is an apocalyptic number.
31110113300323 is a deficient number, since it is larger than the sum of its proper divisors (275310737285).
31110113300323 is a wasteful number, since it uses less digits than its factorization.
31110113300323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275310737284.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 31110113300323 its reverse (32300331101113), we get a palindrome (63410444401436).
The spelling of 31110113300323 in words is "thirty-one trillion, one hundred ten billion, one hundred thirteen million, three hundred thousand, three hundred twenty-three".
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