Base | Representation |
---|---|
bin | 100011010111100100010011… |
… | …0101011010111100001101011 |
3 | 1111210112002102212221211210222 |
4 | 1012233020212223113201223 |
5 | 311234100012331134402 |
6 | 3021354232254400255 |
7 | 122346254154541604 |
oct | 10657104653274153 |
9 | 1453462385854728 |
10 | 311102310021227 |
11 | 9014382664a68a |
12 | 2aa8586620008b |
13 | 10478a8baabb6a |
14 | 56b7609b48dab |
15 | 25e7741e537a2 |
hex | 11af226ad786b |
311102310021227 has 2 divisors, whose sum is σ = 311102310021228. Its totient is φ = 311102310021226.
The previous prime is 311102310021203. The next prime is 311102310021241. The reversal of 311102310021227 is 722120013201113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311102310021227 - 212 = 311102310017131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311102310021196 and 311102310021205.
It is not a weakly prime, because it can be changed into another prime (311102310024227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155551155010613 + 155551155010614.
It is an arithmetic number, because the mean of its divisors is an integer number (155551155010614).
Almost surely, 2311102310021227 is an apocalyptic number.
311102310021227 is a deficient number, since it is larger than the sum of its proper divisors (1).
311102310021227 is an equidigital number, since it uses as much as digits as its factorization.
311102310021227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
The spelling of 311102310021227 in words is "three hundred eleven trillion, one hundred two billion, three hundred ten million, twenty-one thousand, two hundred twenty-seven".
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