Base | Representation |
---|---|
bin | 100011010111100101010010… |
… | …0000001111001001111111001 |
3 | 1111210112021212110020020001212 |
4 | 1012233022210001321033321 |
5 | 311234113314222003041 |
6 | 3021355221102252505 |
7 | 122346360242331146 |
oct | 10657124401711771 |
9 | 1453467773206055 |
10 | 311104413078521 |
11 | 90144705786767 |
12 | 2aa86152587135 |
13 | 104790356ca46a |
14 | 56b776918d3cd |
15 | 25e78168c18eb |
hex | 11af2a40793f9 |
311104413078521 has 2 divisors, whose sum is σ = 311104413078522. Its totient is φ = 311104413078520.
The previous prime is 311104413078517. The next prime is 311104413078533. The reversal of 311104413078521 is 125870314401113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 257991859515625 + 53112553562896 = 16062125^2 + 7287836^2 .
It is a cyclic number.
It is not a de Polignac number, because 311104413078521 - 22 = 311104413078517 is a prime.
It is not a weakly prime, because it can be changed into another prime (311104413078541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155552206539260 + 155552206539261.
It is an arithmetic number, because the mean of its divisors is an integer number (155552206539261).
Almost surely, 2311104413078521 is an apocalyptic number.
It is an amenable number.
311104413078521 is a deficient number, since it is larger than the sum of its proper divisors (1).
311104413078521 is an equidigital number, since it uses as much as digits as its factorization.
311104413078521 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 41.
Adding to 311104413078521 its reverse (125870314401113), we get a palindrome (436974727479634).
The spelling of 311104413078521 in words is "three hundred eleven trillion, one hundred four billion, four hundred thirteen million, seventy-eight thousand, five hundred twenty-one".
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