Base | Representation |
---|---|
bin | 1001000011011111001… |
… | …10100000100011111011 |
3 | 1002202000210101001212212 |
4 | 10201233212200203323 |
5 | 20044123130324011 |
6 | 354531051125335 |
7 | 31322411314343 |
oct | 4415746404373 |
9 | 1082023331785 |
10 | 311110011131 |
11 | 10aa39544087 |
12 | 5036614384b |
13 | 234507936aa |
14 | 110b488bd23 |
15 | 815cc2e08b |
hex | 486f9a08fb |
311110011131 has 2 divisors, whose sum is σ = 311110011132. Its totient is φ = 311110011130.
The previous prime is 311110011053. The next prime is 311110011139. The reversal of 311110011131 is 131110011113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311110011131 is a prime.
It is a super-2 number, since 2×3111100111312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311110011139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155555005565 + 155555005566.
It is an arithmetic number, because the mean of its divisors is an integer number (155555005566).
Almost surely, 2311110011131 is an apocalyptic number.
311110011131 is a deficient number, since it is larger than the sum of its proper divisors (1).
311110011131 is an equidigital number, since it uses as much as digits as its factorization.
311110011131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 14.
Adding to 311110011131 its reverse (131110011113), we get a palindrome (442220022244).
The spelling of 311110011131 in words is "three hundred eleven billion, one hundred ten million, eleven thousand, one hundred thirty-one".
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