Base | Representation |
---|---|
bin | 100011010111101000010110… |
… | …0101101111101110001111001 |
3 | 1111210112220212121010120001002 |
4 | 1012233100230231331301321 |
5 | 311234220312313100324 |
6 | 3021402230530534345 |
7 | 122350012431311204 |
oct | 10657205455756171 |
9 | 1453486777116032 |
10 | 311111001300089 |
11 | 90147486650081 |
12 | 2aa87490a373b5 |
13 | 104798455c9913 |
14 | 56b7bd215a93b |
15 | 25e7a9ee9c3ae |
hex | 11af42cb7dc79 |
311111001300089 has 2 divisors, whose sum is σ = 311111001300090. Its totient is φ = 311111001300088.
The previous prime is 311111001299951. The next prime is 311111001300101. The reversal of 311111001300089 is 980003100111113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 262138507438864 + 48972493861225 = 16190692^2 + 6998035^2 .
It is a cyclic number.
It is not a de Polignac number, because 311111001300089 - 224 = 311110984522873 is a prime.
It is not a weakly prime, because it can be changed into another prime (311111001308089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155555500650044 + 155555500650045.
It is an arithmetic number, because the mean of its divisors is an integer number (155555500650045).
Almost surely, 2311111001300089 is an apocalyptic number.
It is an amenable number.
311111001300089 is a deficient number, since it is larger than the sum of its proper divisors (1).
311111001300089 is an equidigital number, since it uses as much as digits as its factorization.
311111001300089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 29.
The spelling of 311111001300089 in words is "three hundred eleven trillion, one hundred eleven billion, one million, three hundred thousand, eighty-nine".
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