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311121320113 = 931133414383
BaseRepresentation
bin1001000011100000100…
…01101001100010110001
31002202001120122121220001
410201300101221202301
520044134024220423
6354532133350001
731322606405212
oct4416021514261
91082046577801
10311121320113
1110aa4496874a
1250369a98301
1323452c22cb6
14110b6193409
15815dc14cad
hex48704698b1

311121320113 has 4 divisors (see below), whose sum is σ = 311154743808. Its totient is φ = 311087896420.

The previous prime is 311121320087. The next prime is 311121320119. The reversal of 311121320113 is 311023121113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311121320113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311121320119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16697881 + ... + 16716502.

It is an arithmetic number, because the mean of its divisors is an integer number (77788685952).

Almost surely, 2311121320113 is an apocalyptic number.

It is an amenable number.

311121320113 is a deficient number, since it is larger than the sum of its proper divisors (33423695).

311121320113 is an equidigital number, since it uses as much as digits as its factorization.

311121320113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33423694.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 311121320113 its reverse (311023121113), we get a palindrome (622144441226).

The spelling of 311121320113 in words is "three hundred eleven billion, one hundred twenty-one million, three hundred twenty thousand, one hundred thirteen".

Divisors: 1 9311 33414383 311121320113