Base | Representation |
---|---|
bin | 101101010001100011001… |
… | …011100111100010011001 |
3 | 102000102121021220112110222 |
4 | 231101203023213202121 |
5 | 401433234344442332 |
6 | 10341135212445425 |
7 | 440530640212103 |
oct | 55214313474231 |
9 | 12012537815428 |
10 | 3111220312217 |
11 | a9a508836486 |
12 | 422b85479875 |
13 | 197504ab3834 |
14 | aa8261b6573 |
15 | 55de3a3a712 |
hex | 2d4632e7899 |
3111220312217 has 2 divisors, whose sum is σ = 3111220312218. Its totient is φ = 3111220312216.
The previous prime is 3111220312171. The next prime is 3111220312223. The reversal of 3111220312217 is 7122130221113.
3111220312217 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3003389514841 + 107830797376 = 1733029^2 + 328376^2 .
It is a cyclic number.
It is not a de Polignac number, because 3111220312217 - 212 = 3111220308121 is a prime.
It is not a weakly prime, because it can be changed into another prime (3111220012217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555610156108 + 1555610156109.
It is an arithmetic number, because the mean of its divisors is an integer number (1555610156109).
Almost surely, 23111220312217 is an apocalyptic number.
It is an amenable number.
3111220312217 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111220312217 is an equidigital number, since it uses as much as digits as its factorization.
3111220312217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 26.
The spelling of 3111220312217 in words is "three trillion, one hundred eleven billion, two hundred twenty million, three hundred twelve thousand, two hundred seventeen".
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