Base | Representation |
---|---|
bin | 1110001001011111001110… |
… | …11001010111001010110011 |
3 | 11002011022100210102012010222 |
4 | 13010233213121113022303 |
5 | 13034221023024412243 |
6 | 150100450210043255 |
7 | 6360535356130313 |
oct | 704574731271263 |
9 | 132138323365128 |
10 | 31112330310323 |
11 | 9a057353aa759 |
12 | 35a594057952b |
13 | 1448b59930122 |
14 | 797bb8295443 |
15 | 38e482ee5168 |
hex | 1c4be76572b3 |
31112330310323 has 2 divisors, whose sum is σ = 31112330310324. Its totient is φ = 31112330310322.
The previous prime is 31112330310301. The next prime is 31112330310337. The reversal of 31112330310323 is 32301303321113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31112330310323 - 238 = 30837452403379 is a prime.
It is a super-2 number, since 2×311123303103232 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31112330310292 and 31112330310301.
It is not a weakly prime, because it can be changed into another prime (31112330310353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556165155161 + 15556165155162.
It is an arithmetic number, because the mean of its divisors is an integer number (15556165155162).
Almost surely, 231112330310323 is an apocalyptic number.
31112330310323 is a deficient number, since it is larger than the sum of its proper divisors (1).
31112330310323 is an equidigital number, since it uses as much as digits as its factorization.
31112330310323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 31112330310323 its reverse (32301303321113), we get a palindrome (63413633631436).
The spelling of 31112330310323 in words is "thirty-one trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, three hundred twenty-three".
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